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Math Help - A question of how this problem can be solved

  1. #1
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    A question of how this problem can be solved

    Hi there you guys can see the problem here

    PicPaste - 20140824_105133-N1SKFQCV.jpg

    Actually when I solve it i get something else

    16MC/1.5 + 15360 / 4*1.5 + 2MC*4 + (3*60*4^2) / 6

    I later get

    10,66 MC + 2560 + 8MC + 480

    which gives me

    MC =-162

    what have I done wrong if so,could someone show me how to solve it properly? Thank you
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  2. #2
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    Re: A question of how this problem can be solved

    what was the original problem and the given?
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  3. #3
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    Re: A question of how this problem can be solved

    Quote Originally Posted by Riazy View Post
    Hi there you guys can see the problem here

    PicPaste - 20140824_105133-N1SKFQCV.jpg

    Actually when I solve it i get something else

    16MC/1.5 + 15360 / 4*1.5 + 2MC*4 + (3*60*4^2) / 6

    I later get

    10,66 MC + 2560 + 8MC + 480

    which gives me

    MC =-162

    what have I done wrong if so,could someone show me how to solve it properly? Thank you
    The information you have given is insufficient to solve anything. For example, sometimes it appears that L = 8, but sometimes it appears that L = 4. If some of the variables in the first line are assigned values, what are those assigned values?

    Moreover, the transition from the first line to the second line is very odd. For example, how does

    $L = 8 \implies \dfrac{2M_cL}{6EI} = \dfrac{2M_c * 8}{6EI * 1.5}?$

    Of course, maybe L = 4. How does $L = 4 \implies \dfrac{2M_cL}{6EI} = \dfrac{2M_c * 8}{6EI * 1.5}?$

    The third line is not even an equation. But it seems to imply that EI = 1. Is that correct?

    The fourth line introduces some undefined variables that have not been seen before.

    How are you using periods and commas? It appears that you are using the European convention sometimes and the American convention sometimes. We can probably cope with either convention, but not a mixture.
    Thanks from topsquark
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