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  1. #1
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    exponential

    13 The volume of chlorine, C litres, in a swimming pool at time t hours after it was placed in
    the pool can be modelled by C(t) = C0ekt, t ≥ 0. The volume of chlorine in the pool is
    decreasing. Initially the volume of chlorine in the pool was 3 litres, 8 hours later the
    volume was 2.5 litres.
    a State the value of C0.
    b Find the exact value of k.
    c Exactly how many litres of chlorine were present in the pool 16 hours after the
    chlorine was added to the pool?

    i need help on c. how would i do this question.
    i sub t=16, Co=3 in the equation but do know what to do next.
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  2. #2
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    Quote Originally Posted by rachael
    13 The volume of chlorine, C litres, in a swimming pool at time t hours after it was placed in
    the pool can be modelled by C(t) = C0ekt, t ≥ 0. The volume of chlorine in the pool is
    decreasing. Initially the volume of chlorine in the pool was 3 litres, 8 hours later the
    volume was 2.5 litres.
    a State the value of C0.
    b Find the exact value of k.
    c Exactly how many litres of chlorine were present in the pool 16 hours after the
    chlorine was added to the pool?

    i need help on c. how would i do this question.
    i sub t=16, Co=3 in the equation but do know what to do next.
    Hello,

    to a) $\displaystyle C_0=3\ell$
    to b) $\displaystyle c(8)=2.5=3 \cdot e^{k \cdot 8}\ \Rightarrow \ k=\frac{1}{8} \cdot (ln(5)-ln(6))$
    that means $\displaystyle k\approx -0.02279...$
    to c) Now you've got all the values you need to do the last problem. Plug in t=16 into your equation and you'll get:
    $\displaystyle c(16)=3 \cdot e^{\frac{1}{8} \cdot (ln(5)-ln(6)) \cdot 16}=\frac{25}{12} \ell$

    Maybe you're a little bit astonished that you get an exakt rational number with c). The problem c) could be done using the results of problem b):
    $\displaystyle c(8)=2.5=3 \cdot e^{k \cdot 8} \Longleftrightarrow \frac{5}{6}=e^{k \cdot 8}$
    $\displaystyle e^{k \cdot 16}=e^{{k \cdot 8} \cdot 2}=\left(e^{k \cdot 8} \right)^2 = \frac{25}{36}$
    so you get:$\displaystyle c(16)=3 \cdot \frac{25}{36}=\frac{25}{12}$
    as I've shown above.

    Greetings

    EB
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  3. #3
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    thank you
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