$\displaystyle |x+3| = |2x+1|$

How do we go about solving this? I know there are two cases when x>0 and when x<0, but how do we set it up afterwards?

Edit: I may have solved this:

Case 1: If x > 0, then

$\displaystyle x+3 = 2x +1 $

$\displaystyle x=2 $

Case 2: If x < 0. then

$\displaystyle -(x+3) = - (2x+1) $

$\displaystyle x=2$

So we can conclude that the solution to the system is at x=2?

I checked Wolfram but they have a solution of $\displaystyle \frac{-4}{3}$ http://www.wolframalpha.com/input/?i...3D%7C2x%2B1%7C

Any Help is appreciated.