We have two fourth powers and one sqare beneath monomyals Let us try enshorted multiplyig formulas
if we odd bothsidely x^{2}y^{2} we have
=our formula
So I am working my way through an algebra practice book, and I am stumped on this question:
4x^4 + (3x^2)(y^2) + y^4
Now the answer is listed as (2x^2 + xy + y^2)(2x^2 - xy + y^2)
What steps does one take to obtain this answer?
Thanks
We have two fourth powers and one sqare beneath monomyals Let us try enshorted multiplyig formulas
if we odd bothsidely x^{2}y^{2} we have
=our formula
Thanks, but I am still confused. What steps do you use to derive that answer? Also, you wrote initially , did you mean ?
Another example is the following problem:
Do I just add and subtract from this? I find that the two factors of 16 are -4 and -4, so if I add and subtract from the problem, I get . This I can then factor into the answer.
I used some guesswork to get this though, by knowing that is . So I assumed then that since + is , then I then assumed I subtract from the other side.
Are problems like this solved by some guessing/trial-and-error, or is there a specific step I am missing?