Hello, ff4930!
Quite a project . . .
I do not know how I got this on my notes in the next step:
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I was rushing on copying my notes and I do not know how this:
5(35(3^n-1) - 29(2^n-1) ) - 6(35(3^n-2) - 29(2^n-2) )
=
(the 6 in the 2nd portion can be written as 2*3)
5*35(3^n-1) - 5*29(2^n-1) - 2*35(3^n-1) + 3*29(2^n-1)
this is where I do not know how I got this on my notes in the next step.
= 3*35*(3^n-1) - 2*29(2^n-1)
=35*(3^n) - 29(2^n)
anyone know how I get = 3*35*(3^n-1) - 2*29(2^n-1), thanks in advance.