In how many ways can 2310 be expressed as a product of 3 factors ? ( This will not involve Combinatorics analysis !)
same as Soroban brute force list except I included 1 as a possible factor, and the first two factors don't have to be prime numbers
such as 6 11 35 and 7 10 33 are included in the list
There are 16 triplets of the form {1,y,z} since there are 32 divisors of 2310
I don't know how but I sense that there is a way to count the remaining 25. Is that what you are after?