Originally Posted by

**mkjmn** Please show step by step how to solve long division method of;

(3x^2 -x+x^3-3) / (x^2+4x+3)

Hello,

first rearrange dividend and divisor so that the powers of x are written in descending order:

(x^3 + 3x^2 - x - 3) / (x^2 + 4x + 3)

I assume that you know how to do long division: Code:

(x^3 + 3x^2 - x - 3) ÷ (x^2 + 4x + 3) = x - 1
-(x^3 + 4x^2 + 3x)
-------------------
-x^2 - 4x - 3
-(-x^2 - 4x - 3)
------------------------
0

Because the remainder is zero the dividend is a multiple of the divisor.