Solve the equation system:
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Originally Posted by james_bond Solve the equation system: Power to 5 the first equation: So And May be you can go on from there.
Originally Posted by james_bond Solve the equation system: I'd recommend the brute force approach. The rational root theorem gives -1 and 2 as zeros. So do long or synthetic division, which will give you a quadratic to solve at the end. -Dan
Step 1 (The Krizalid Operation) . . . [1] Step 2 . . . (use [1]) . . . [2] Step 3 . . . (use [2]) . . . [3] Step 4 . . . (use [3]) . . . (use 2) So you just have to solve, Where is one of those possible values.
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