Solve the equation system:
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Originally Posted by james_bond Solve the equation system: Power to 5 the first equation:
May be you can go on from there.
Originally Posted by james_bond Solve the equation system: I'd recommend the brute force approach.
The rational root theorem gives -1 and 2 as zeros. So do long or synthetic division, which will give you a quadratic to solve at the end.
Step 1 (The Krizalid Operation) . . .  Step 2 . . . (use ) . . .  Step 3 . . . (use ) . . .  Step 4 . . . (use ) . . . (use 2)
So you just have to solve,
Where is one of those possible values.
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