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  1. #1
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    how in the world

    how in the world do u solve this?

    ((2z)2 (x4)3) ((x2)-2(4z)2)



    the final answer must contain positive exponents
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  2. #2
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    Hello, tdot!

    I must assume you know the basic rules for exponents . . .


    \frac{(2z)^2(x^4)^3}{(x^2)^{-2}(4z)^2}

    We have: . \frac{2^2\cdot z^2\cdot x^{12}}{x^{-4}\cdot4^2\cdot z^2} \;=\;\frac{4\cdot x^{12}\cdot z^2}{16\cdot x^{-4}\cdot z^2} \;=\;\frac{x^{16}}{4}

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  3. #3
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    ok. its making more sence. i have other questions, that i tried out but wanna be sure that i have it right.


    (2/x2)3 (x5)-2 (x/4)-1
    (a2b3c)4 ( 3abc)2

    (1+i)5 (1+i)-8

    (y2/3 y1/3 y1/2) (y-6)
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  4. #4
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    Quote Originally Posted by tdot View Post
    ok. its making more sence. i have other questions, that i tried out but wanna be sure that i have it right.


    (2/x2)3 (x5)-2 (x/4)-1
    (a2b3c)4 ( 3abc)2

    (1+i)5 (1+i)-8

    (y2/3 y1/3 y1/2) (y-6)
    Hello,

    1. If you have a new problem start a new thread.
    2. Use this sign ^ to write a power (or learn how to write in Latex)
    3. Use brackets to separate bases, exponents, factors or summands.

    I assume that you meant:
    \left(\frac2{x^2}\right)^3 \cdot (x^5)^{-2} \cdot \left(\frac x4\right)^{-1} Transcribe this term into a product:

    (2x^{-2})^3 \cdot (x^5)^{-2} \cdot (4^{-1} x)^{-1} Expand the brackets:

    8 x^{-6} \cdot x^{-10} \cdot 4 x^{-1}=32x^{-17}=\frac{32}{x^{17}}
    = = = = = == = = = = = = = = = = = = = = = = = = = = = = = = = = =
    \frac{(a^2 b^3 c)^4}{(3 a b c)^2}=(a^2 b^3 c)^4 \cdot (3 a b c)^{-2} Expand and collect like terms. I've got:

    \frac19 \cdot a^6 \cdot b^{10}  \cdot c^2

    = = = = = == = = = = = = = = = = = = = = = = = = = = = = = = = = =

    (y^(2/3) y^(1/3) y^(1/2)) (y^(-6)) ==> \frac{y^{\frac23} \cdot y^{\frac13} \cdot y^{\frac12} }{y^{-6}}=y^{\frac32} \cdot y^6=y^{\frac{15}2}=\sqrt{y^{15}}
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