Hi friends.

Please can you say me what is the correct way to solve this problem? Thank you

A rectangular area with a square at its center. If the long side of rectangle is more large than short side in 8 and the side of square is (1/10) of the short side of rectangle, the area A (area without square) is.....

if x: short side, then A=x(x+8)-(1/10)(x)

or x: long side, then A=(x-8)x-(1/10)(x-8)