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Thread: Solving logarithmic equation

  1. November 18th 2007, 02:39 PM #1
    Geraldine Biggs
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    Solving logarithmic equation

    log2(x-6)+log2(x-4)-log2x=2
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  2. November 18th 2007, 02:43 PM #2
    Jhevon
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    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by Geraldine Biggs View Post
    log2(x-6)+log2(x-4)-log2x=2
    recall that \log_a x + \log_a y = \log_a xy and \log_a x - \log_a y = \log_a \left(\frac xy \right)

    thus,

    \log_2 (x - 6) + \log_2 (x - 4) - \log_2 x = \log_2 \left[ \frac {(x - 6)(x - 4)}{2x} \right] = 2

    can you continue?
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