log2(x-6)+log2(x-4)-log2x=2

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- Nov 18th 2007, 02:39 PMGeraldine BiggsSolving logarithmic equation
log2(x-6)+log2(x-4)-log2x=2

- Nov 18th 2007, 02:43 PMJhevon
recall that $\displaystyle \log_a x + \log_a y = \log_a xy$ and $\displaystyle \log_a x - \log_a y = \log_a \left(\frac xy \right)$

thus,

$\displaystyle \log_2 (x - 6) + \log_2 (x - 4) - \log_2 x = \log_2 \left[ \frac {(x - 6)(x - 4)}{2x} \right] = 2$

can you continue?