Hello,
I do not know if this is the right place to post this question, but I believe it falls under algebra. Please redirect me if appropriate.
Question:
How can I show that $$P-QR^3<\frac{R^4}{C}$$ for $$C,P,Q,R > 0?$$
Thanks.
Hello,
I do not know if this is the right place to post this question, but I believe it falls under algebra. Please redirect me if appropriate.
Question:
How can I show that $$P-QR^3<\frac{R^4}{C}$$ for $$C,P,Q,R > 0?$$
Thanks.
You cannot show it because it is not true.
Example. Let R = 2, C = 4, P = 100, Q = 3
$P - QR^3 = 100 - 3 * 2^3 = 100 - 3 * 8 = 100 - 24 = 76.\ And\ \dfrac{R^4}{C} = \dfrac{2^4}{4} = \dfrac{16}{4} = 4.$
$76 \not < 4.$
There must be additional constraints that you have not specified.