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Math Help - Equation

  1. #1
    Junior Member fluffy_penguin's Avatar
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    Exclamation Equation



    9x^2-12x+1=0

    And since I couldn't go any further with it I thought it might be no solution

    (3x -?)(3x -?)
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by fluffy_penguin View Post


    9x^2-12x+1=0

    And since I couldn't go any further with it I thought it might be no solution

    (3x -?)(3x -?)
    you're doing complex numbers now right? which means your quadratics will always have solutions, just perhaps, not real ones.

    if factoring is a problem, use the quadratic formula
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  3. #3
    Math Engineering Student
    Krizalid's Avatar
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    9x^2-12x+1=(3x-2)^2-3.
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  4. #4
    Junior Member fluffy_penguin's Avatar
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    To be honest, I'm still confused. We're on the radical chapters, I don't know why I got asked that question. But I'll try the quadratic forumla for it.
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  5. #5
    Math Engineering Student
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    Sure.

    Then you want an expression like this

    (3x - 2)^2 - 3 = (3x - 2)^2 - \left( {\sqrt 3 } \right)^2 = \left( {3x - 2 + \sqrt 3 } \right)\left( {3x - 2 - \sqrt 3 } \right).

    Now you have radicals there.
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