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Thread: My first post...

  1. #1

    Talking My first post...

    Find the value of y
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  2. #2
    Super Member
    Oct 2007
    London / Cambridge
    Now this could be solved if you identify the triple, the 3,4,5 tirangle.
    or you can just do the algebra.

    $\displaystyle (y+1)^2 + y^2 = 5^2$
    $\displaystyle y^2+2y+1 + y^2 = 5^2$
    $\displaystyle 2y^2+2y-24 = 0$
    $\displaystyle y^2+y-12 = 0$
    $\displaystyle (y+4)(y-3) = 0$

    remember y is a length so it cannot be negative.

    hope that help.

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