# Math Help - My first post...

1. ## My first post...

Find the value of y

2. Now this could be solved if you identify the triple, the 3,4,5 tirangle.
or you can just do the algebra.

$(y+1)^2 + y^2 = 5^2$
$y^2+2y+1 + y^2 = 5^2$
$2y^2+2y-24 = 0$
$y^2+y-12 = 0$
$(y+4)(y-3) = 0$

remember y is a length so it cannot be negative.

hope that help.

bobak