Originally Posted by

**Lexielai** Hello everybody!

These two problems have been boggling me for awhile now:

**#1)1/(1+1/x) = a Find all values of "a" that yield no solution for "x"**

**#2)(6x-a)/(x-3) = 3 Find all values of "a" that yield no solution for "x" **

I'm unsure of how to solve for this type of solution, but I've tried isolating the "x" variables like so:

**#1) 1/(1+1/x) = a**

*1) *1 = a + a/x

*2) *1 - a = a/x

*3) *x/a = 1/(1-a)

* 4)* x = a/(1-a)

**#2) (6x-a)/(x-3) = 3**

* 1) *6x - a = 3x - 9

2) 3x - a = -9

* 3) *3x = a - 9

* 4) *x = a/3 - 3

However, I don't really know how to express "x" as a no solution value to be solved for, so I may have made errors in my steps. If someone could lend me some insight, I would be very grateful!