Hi Everybody. First technical post on here, need help with a high school grade10 Algebra question included in a section on Quadratic equations.
I've never seen a q like this so really not sure how to approach it.

Express b in terms of j
8 - {(b2 - 64)j} + b = 181/2

Tried several angles of expanding the expressions but can't get down to anything that helps me simplify further.
Here are some of the approaches I tried.

1.
- (b+8)(b-8)j + (b+8) = 181/2
(b+8)(b-8)j - (b+8) = - 181/2
(b+8).[(b-8)j - 1] = - 181/2

Not sure what to do next. Tried a few other approaches but still can't see I'm on the right track.

Any suggestions?
(and I also hope this doesn't get demoted down to the "normal" Algebra section)

Thanks.

2. ## Re: Quadratic (??) equation

But it IS "normal" Algebra, this section is for Advanced algebra, such as the study of vector spaces and groups.

Since we are solving an equation with "$b$" as the variable, we can re-write it like so:

$(-64j)b^2 + b + (8 - 64j - \sqrt{18}) = 0$

This is a quadratic equation in $b$, with solution:

$b = \dfrac{-1 \pm \sqrt{1 + (4)(64j)(8-64j -\sqrt{18})}}{-128j}$

It is unclear from your problem whether or not $j$ is intended to be a square root of -1.