Hi Everybody. First technical post on here, need help with a high school grade10 Algebra question included in a section on Quadratic equations.
I've never seen a q like this so really not sure how to approach it.

Express b in terms of j
8 - {(b2 - 64)j} + b = 181/2

Tried several angles of expanding the expressions but can't get down to anything that helps me simplify further.
Here are some of the approaches I tried.

1.
- (b+8)(b-8)j + (b+8) = 181/2
(b+8)(b-8)j - (b+8) = - 181/2
(b+8).[(b-8)j - 1] = - 181/2

Not sure what to do next. Tried a few other approaches but still can't see I'm on the right track.

Any suggestions?
(and I also hope this doesn't get demoted down to the "normal" Algebra section)

Thanks.

But it IS "normal" Algebra, this section is for Advanced algebra, such as the study of vector spaces and groups.

Since we are solving an equation with "$b$" as the variable, we can re-write it like so:

$(-64j)b^2 + b + (8 - 64j - \sqrt{18}) = 0$

This is a quadratic equation in $b$, with solution:

$b = \dfrac{-1 \pm \sqrt{1 + (4)(64j)(8-64j -\sqrt{18})}}{-128j}$

It is unclear from your problem whether or not $j$ is intended to be a square root of -1.