Solve by the method of your choice. x^2+y^2=50 (x-7)^2+y^2=1 I got; {(7,1), (7,-1),(-7,1),(-7,-1)} x^2+y^2=29 -8x+y^2=41 I got: {(-2,5),(-2.-5)}
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Originally Posted by soly_sol Solve by the method of your choice. x^2+y^2=50 (x-7)^2+y^2=1 I got; {(7,1), (7,-1),(-7,1),(-7,-1)} you know, you could check your solutions by plugging into the original system. you would have immediately realize that (-7,-1) and (-7,1) do not work in the second equation, so those solutions are wrong your answer to the second is ok
Originally Posted by soly_sol Solve by the method of your choice. x^2+y^2=50 (x-7)^2+y^2=1 I got; {(7,1), (7,-1),(-7,1),(-7,-1)} what did you do? what is $\displaystyle (-7 - 7)^2 + ( \pm 1)^2$? Originally Posted by soly_sol x^2+y^2=29 -8x+y^2=41 I got: {(-2,5),(-2.-5)} right! but i think, there is more.. EDIT: no more.. Ü
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