Have homework on indices as follows but unable to solve. Any help is appreciated.
2) 12^x/3^x-1 multiply 4^x+1/2
3) 24^x//2^3x+1 multiply [3^x+1/2^2x+1]^-2
thank you so much
Thank you for your prompt response.
1) for 1, I cancel out 3x on top and bottom and I got 4x/⅓ which gives
4 x .3
Am i correct?
2) I realise I type wrongly for 2. the question is
(12^x)/3^(x-1) multiply (4^(x+1))/2
3) sorry, typo error again, it should be
24^x/2^(3x+1) multiply [3^(x+1)/2^(2x+1)]^-2