Have homework on indices as follows but unable to solve. Any help is appreciated.

Evaluate

1) 12^x/3^x-1

2) 12^x/3^x-1 multiply 4^x+1/2

3) 24^x//2^3x+1 multiply [3^x+1/2^2x+1]^-2

thank you so much

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- November 17th 2007, 06:11 AMkristyneoindices
Have homework on indices as follows but unable to solve. Any help is appreciated.

Evaluate

1) 12^x/3^x-1

2) 12^x/3^x-1 multiply 4^x+1/2

3) 24^x//2^3x+1 multiply [3^x+1/2^2x+1]^-2

thank you so much - November 17th 2007, 06:38 AMearboth
- November 17th 2007, 07:33 AMkristyneo
Thank you for your prompt response.

1) for 1, I cancel out 3x on top and bottom and I got 4x/⅓ which gives

4 x .3

Am i correct?

2) I realise I type wrongly for 2. the question is

(12^x)/3^(x-1) multiply (4^(x+1))/2

3) sorry, typo error again, it should be

24^x/2^(3x+1) multiply [3^(x+1)/2^(2x+1)]^-2 - November 17th 2007, 08:59 AMearboth
- November 17th 2007, 10:52 AMSoroban
Hello, kristyneo!

I have to**guess**what you meant . . .

Quote:

Quote:

. .

Quote:

We have: .

. .

- November 17th 2007, 11:02 PMkristyneo
Thank you all,

You have been a great help !!!