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Math Help - Dividing Rational expressions

  1. #1
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    Dividing Rational expressions

    i don't think that the answer in the book is right for this one

    \frac{15a^2b}{4c} \div \frac{8abc}{-3}

    i know that you have to times it by the reciprocal
    the non-reduced answer that i got is:

    -\frac{45a^2b}{60a^2bc}

    the only way that i can think to reduce this is by dividing the top and bottom by 5 but that leaves 9 on the top and 12 on the bottom which can be reduced further.
    also
    the answer in the back of the book is

    -\frac{45a}{32c^2}
    is this the correct answer??
    how do you get it if it is.
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  2. #2
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    Quote Originally Posted by t-dot View Post
    i don't think that the answer in the book is right for this one

    \frac{15a^2b}{4c} \div \frac{8abc}{-3}

    i know that you have to times it by the reciprocal
    the non-reduced answer that i got is:

    -\frac{45a^2b}{60a^2bc}

    the only way that i can think to reduce this is by dividing the top and bottom by 5 but that leaves 9 on the top and 12 on the bottom which can be reduced further.
    also
    the answer in the back of the book is

    -\frac{45a}{32c^2}
    is this the correct answer??
    how do you get it if it is.
    Hi,
    the answer in your book is correct:

    \frac{15a^2b}{4c} \div \frac{8abc}{-3}= \frac{15a^2b}{4c} \cdot \frac{-3}{8abc}

    As you easily can see you calculated 4 \cdot 8 = 60 which isn't correct too often

    Don't forget to cancel the a's and b's.
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  3. #3
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    whooops.... LOL ... thanks so much
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