how to solve: z^4+13z^2+36
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Originally Posted by baidyasuyam how to solve: z^4+13z^2+36 $u=z^2$ $u^2+13u+36$ $(u+9)(u+4)$ $(z^2+9)(z^2+4)$ Thats as far as it will go assuming real numbers. If z can be complex $(z+3\imath)(z-3\imath)(z+2\imath)(z-2\imath)$
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