Originally Posted by

**hennanra** Hello,

I am new to algebra and would really appreciate some analysis of the logic of the following equation. I am working through a textbook on fundamentals of mathematics and we start with the original equation:

$\displaystyle \frac{\sqrt{3x^2+x}}{2\sqrt{x}}=7$

To remove the square root and simplify the equation we square each side of the equation and the resulting formula is:

$\displaystyle \frac{3x^2+x}{4x}=49$

Upto that part I am fine. Next, the text book says that we should cancel x in the numerator and denominator on the left hand side only. I understand why we are only doing it on the left hand side - i.e. we are cancelling down to the simplest expression. However, I don't quite understand how we end up with the following equation after cancelling out i.e.:

$\displaystyle \frac{(3x+1)}{4}=49$

Kind Regards,

Raheel