# Word Problem work

• Nov 14th 2007, 04:31 PM
AHDDM
Word Problem work
Two Workers do a job in 12 hours working together

One worker does half then other one does other half they finish in 25 days

how long will it take each alone?

I need thins really fast if someone can give me equations i can solve but i am only able to get 1st one

$\displaystyle (1/12)x+(1/12)y=1$
• Nov 14th 2007, 05:19 PM
ThePerfectHacker
Quote:

Originally Posted by AHDDM
Two Workers do a job in 12 hours working together

One worker does half then other one does other half they finish in 25 days

how long will it take each alone?

I need thins really fast if someone can give me equations i can solve but i am only able to get 1st one

$\displaystyle (1/12)x+(1/12)y=1$

I think you means 12 days not hours.

Let $\displaystyle x$ be the time it takes the first worker. Let $\displaystyle y$ be the time it takes the second worker. When working together we have $\displaystyle \frac{12}{x}+\frac{12}{y} = 1$. When the first worker does half the full job in $\displaystyle x$ days so it takes him $\displaystyle x/2$ days to do half-the job. Likewise it does the other worker $\displaystyle y/2$ days. So $\displaystyle x/2+y/2 = 25$. Now solve these equations.
• Nov 14th 2007, 05:23 PM
AHDDM
thank you solving them now :)

Hmmm i got it solutions are 20 and 30
• Nov 14th 2007, 06:38 PM
ThePerfectHacker
I got that too.