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Math Help - to solve the equation

  1. #1
    Junior Member
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    to solve the equation

    Please help to solve the following equation. At the end of the calculation, I dont know how to factorise the equation. Please help me with simple steps
    (x+1/x-2 + 3x) - (1/x+1) = 6

    to solve the equation-solvequation.jpg

    With Many Thanks
    Alan Paul
    Last edited by alanpaul; April 9th 2014 at 10:54 PM. Reason: modify
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  2. #2
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    Re: to solve the equation

    Quote Originally Posted by alanpaul View Post
    Please help to solve the following equation. At the end of the calculation, I dont know how to factorise the equation. Please help me with simple steps
    (x+1/x-2 + 3x) - (1/x+1) = 6

    Click image for larger version. 

Name:	solvequation.jpg 
Views:	4 
Size:	4.7 KB 
ID:	30657

    With Many Thanks
    Alan Paul
    $\dfrac{x+1}{x-2}+\dfrac{3x-1}{x+1}=6$

    $\dfrac{(x+1)^2+(3x-1)(x-2)}{(x-2)(x+1)}=6$

    $\dfrac{x^2+2x+1+3x^2-7x+2}{(x-2)(x+1)}=6$

    $\dfrac{4x^2-5x+3}{x^2-x-2}=6$

    $4x^2-5x+3=6(x^2-x-2)=6x^2-6x-12$

    $2x^2-x-15=0$

    $(x-3)(2x+5)=0$

    $x=3$ OR $x=-\dfrac 5 2$
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