# Simple conversion problem.

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• Mar 12th 2014, 05:22 PM
astuart
Simple conversion problem.
Hi,
I have this problem that I can't figure out. I've had quite a few attempts, but am really not sure where I'm going wrong. It's a simple question, so I'm sure it's something silly I'm doing...

Anyway,

A flash flood left a 200 hectare property ankle deep (100 mm) in water. How much water is this in mega litres? (1 hectare = 100m x 100m. 1 litre = 1000 cm3)

So, if 1 hectare = 100m2, then 200 hectare = 20,000m2.

Based on this, to determine the volume of water, we could multiply the area by the height of the water - 100mm, or 0.1m. 20,000m2 * 0.1m = 2,000m3.

I now have to convert this to litres, and by knowing that 1L = 1cm3, I should convert m3 to cm3. 1 m3 = 1,000,000cm3, so 2,000m3 = 2,000,000,000cm3.

Now, if 1 L is equal to 1000cm3, then 20,000,000,000cm3 = 2,000,000L.

Then, if 1 Megalitre = 1,000,000 L, then 2,000,000L = 2 megalitres.

However, according to the quiz sheet, this is incorrect...Could someone please explain?
,

• Mar 12th 2014, 07:01 PM
romsek
Re: Simple conversion problem.
1 hectare is 10000 \$m^2\$ not 100
• Mar 13th 2014, 08:12 AM
Hartlw
Re: Simple conversion problem.
Systematically, and without thinking about it:

1hct•10000(m2/hct)•100mm•1m/1000mm•1L/1000cm3•(100cm/m)3•1megaL/106L= 1megaL

ck units: hct•m2/hct•m•L/cm3•cm3/m3•megaL/L=megaL
• Mar 13th 2014, 08:56 AM
Shakarri
Re: Simple conversion problem.
1 Litre is 1 dm3, or 1000 cm3
• Mar 13th 2014, 09:06 AM
Hartlw
Re: Simple conversion problem.
Quote:

Originally Posted by Shakarri
1 Litre is 1 dm3, or 1000 cm3

ie, 1L/1000cm3

1hct•10000(m2/hct)•100mm•1m/1000mm•1L/1000cm3•(100cm/m)3•1megaL/106L= 1megaL

You missed the point.
• Mar 13th 2014, 11:28 AM
Shakarri
Re: Simple conversion problem.
I was replying to astuart not to you. I can see what you did but without explanation it might not make sense, your "without thinking about it" approach doesn't help much with understanding.
• Mar 13th 2014, 11:45 AM
Hartlw
Re: Simple conversion problem.
The standard procedure for unit conversion is:

Quote:

Originally Posted by Hartlw
Systematically, and without thinking about it:

1hct•10000(m2/hct)•100mm•1m/1000mm•1L/1000cm3•(100cm/m)3•1megaL/106L= 1megaL

ck units: hct•m2/hct•m•L/cm3•cm3/m3•megaL/L=megaL

You can use any units you want as long as they cancel out- it's a mechanical procedure.

If you have a different way, use it.

Post #4 was trivial and irrelevant.
• Mar 13th 2014, 11:58 AM
Shakarri
Re: Simple conversion problem.
Quote:

Post #4 was trivial and irrelevant.
My post was a follow on from romsek's.
Your post might not have been clear. You can't seem to see it from the perspective of someone who doesn't understand unit conversion. It looks like gibberish if someone is missing just a bit of understanding of what you are doing. For example, depending on what level of pre-university they are in they might not have used dot notation as multiplication. My opinion was that you took too much pre-requisite knowledge for granted and that it might not be understood so assuming that your post was overlooked because it was confusing he would have romsek's hint and my hint which correct his mistakes allowing him to finish the problem by himself.

Quote:

If you have a different way, use it.
I am here to teach
• Mar 13th 2014, 12:02 PM
Hartlw
Re: Simple conversion problem.
Quote:

Originally Posted by Shakarri
1 Litre is 1 dm3, or 1000 cm3

By definition, i liter is a volume of 10cmX10cmX10cm. or 1L/1000cm3 which astuar used in OP.
• Mar 13th 2014, 12:04 PM
Shakarri
Re: Simple conversion problem.
Ah yes, you are right, he did. I only read where he said "I now have to convert this to litres, and by knowing that 1L = 1cm3"
• Mar 13th 2014, 12:04 PM
Hartlw
Re: Simple conversion problem.
Quote:

Originally Posted by Shakarri
I am here to teach

So teach. How would you solve OP?
• Mar 13th 2014, 12:13 PM
Shakarri
Re: Simple conversion problem.
Quote:

Originally Posted by Hartlw
So teach. How would you solve OP?

I don't solve the problems I help the OP solve the problem by guiding them so that they can make their own realizations and then understand the mathematics on a deeper level.
• Mar 13th 2014, 12:40 PM
Hartlw
Re: Simple conversion problem.
(mi/gal)gal=mi, does that require explanation?
ex: (5mi/gal)3gal=15mi

(mi/gal)(1.609km/mi)(1gal/3.79L)=.434km/L
1mi/gal=.434km/L
5mi/gal = 5(.434km/L) = (2.17)km/L, or
5mi/gal(.434km/L)/(1mi/gal) = (2.17)km/L, or, directly:
(5mi/gal)(1.609km/mi)(1gal/3.79L)= (2.17)km/L

I look forward to OP’s solution using your’s and romsek’s guidelines.

I will admit it's easier to "see" if you can write the terms as a over b instead of a/b.
• Mar 13th 2014, 01:57 PM
Hartlw
Re: Simple conversion problem.
Quote:

Originally Posted by Hartlw
Systematically, and without thinking about it:

1hct•10000(m2/hct)•100mm•1m/1000mm•1L/1000cm3•(100cm/m)3•1megaL/106L= 1megaL

ck units: hct•m2/hct•m•L/cm3•cm3/m3•megaL/L=megaL

Good grief! It's 200hct, not 1hct. So the ans is 200ML.

You could have nailed me on that.
• Mar 13th 2014, 03:37 PM
romsek
Re: Simple conversion problem.
Quote:

Originally Posted by Hartlw
Good grief! It's 200hct, not 1hct. So the ans is 200ML.

You could have nailed me on that.

You see, that's the difference here. We're not here to "nail" anyone.
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