Thread: matrices

hi i need to know -

how do you find the inverse of matrix B from:
(I+B)^-1=I-B

where I is the identity matrix, and B is a 4x4 square matrix.

B in this case is:
-7 0 0 8
-6 5 -4 5
-4 4 -3 3
-8 0 0 9

thanks to anyone who can help

I think there is something wrong with the info because:
(I+B)^-1=I-B
<=> I = (I-B)*(I+B)
<=> I = I + B -B -B^2
<=> I = I - B^2
<=> B^2 = 0
which means that B is nilpotent and therefore not invertible.

As you can see the given information is inconsistent.