Hi,

Could someone please show the steps that go to simplifying the below:

[SQRT(6) + 3*SQRT(2)] / [3+SQRT(5)]

Thanks, your help will be greatly appreciated.

Andy

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- Mar 4th 2014, 01:37 AMandy000Simplifying Surd
Hi,

Could someone please show the steps that go to simplifying the below:

[SQRT(6) + 3*SQRT(2)] / [3+SQRT(5)]

Thanks, your help will be greatly appreciated.

Andy - Mar 4th 2014, 02:12 AMromsekRe: Simplifying Surd
$\dfrac{\sqrt{6}+3\sqrt{2}}{3+\sqrt{5}}=\dfrac{ \sqrt{6}+3\sqrt{2}}{3+\sqrt{5}}\cdot 1=$

$\dfrac{\sqrt{6}+3\sqrt{2}}{3+\sqrt{5}}\cdot \dfrac{3-\sqrt{5}}{3-\sqrt{5}}=$

$\dfrac{3\sqrt{6}+9\sqrt{2}-\sqrt{30}-3\sqrt{10}}{9-5}=$

$\dfrac{3\sqrt{6}+9\sqrt{2}-\sqrt{30}-3\sqrt{10}}{4}$

this form should be acceptable. You can tinker with it further to get

$\dfrac{3\sqrt{2}\sqrt{3}+9\sqrt{2}-\sqrt{2}\sqrt{3}\sqrt{5}-3\sqrt{2}\sqrt{5}}{4}=$

$\dfrac{\sqrt{2} \left(3\sqrt{3}+9-\sqrt{3} \sqrt{5}-3\sqrt{5}\right)}{4}=$

$\dfrac{\sqrt{2}\left(3+\sqrt{3}\right)\left(3-\sqrt{5}\right)}{4}$ - Mar 4th 2014, 02:28 AMandy000Re: Simplifying Surd
Thanks very much for the quick reply. I did get the answer out to that first solution, but when I tried to simplify further I made a huge mess of it and figured I had been going about it the wrong way.