# Math Help - One more question

1. ## One more question

Just a couple more im confused about

I have one question that asks me to 'apply the laws of logarithms' to change the form of the following equation

Once again the samples are way easier and dont prepare me I need to change the form so that I can describe the transformations
the result I got was

3log_3(x-4)-1

It feels as if I'm doing it wrong though could you please show me how to get the final form so I can do the transformations?

2. ## Re: One more question

Originally Posted by Rayzala

Once again the samples are way easier and dont prepare me I need to change the form so that I can describe the transformations
the result I got was 3log_3(x-4)-1
I get $3\log_3(x-4)-7$ Recall $3\log_3(9)=6$

3. ## Re: One more question

Originally Posted by Plato
I get $3\log_3(x-4)-7$ Recall $3\log_3(9)=6$
So to find the transformations I would use the first function you gave me right?

Would the description of the transformation be the following?:

The base function is y=log_3x, stretched vertically by 4, and translated right by 4 and down by 13.

4. ## Re: One more question

Originally Posted by Rayzala
So to find the transformations I would use the first function you gave me right?
Would the description of the transformation be the following?:
The base function is y=log_3x, stretched vertically by 4, and translated right by 4 and down by 13.
OH! come on! Learn the basics.

$\dfrac{1}{5}\log_3(9x-36)^{15}-13\\3\left[\log_3(9(x-4))\right]-13\\3\left[2+\log_3(x-4)\right]-13\\6+3\left[\log_3(x-4)\right]-13$

5. ## Re: One more question

Stretched vertically by 5, and translated right by 4 and down by 13?