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Math Help - Factoring

  1. #1
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    Factoring

    solve each equation by factoring and using the zero product property

    1/12x^2 - 2/3x = 4


    ( the x^2 and x are in the middle between the numbers. It is not 12x^2 or 3x )
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  2. #2
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    Re: Factoring

    Quote Originally Posted by catherinee View Post
    solve each equation by factoring and using the zero product property

    1/12x^2 - 2/3x = 4


    ( the x^2 and x are in the middle between the numbers. It is not 12x^2 or 3x )
    so we're talking

    $$\frac{1}{12}x^2-\frac{2}{3}x=4$$

    start by multiplying both sides by 12 and getting all the terms on the left side and 0 on the right side.

    Then factor that quadratic polynomial on the left via one of the methods you've learned. Here if you need a review.

    Then just apply the zero product property to your two factors to obtain your two solutions.
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  3. #3
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    Re: Factoring

    so step 1 would be ---> x^2-8x=48 ?
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  4. #4
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    Re: Factoring

    Yes, and then x^2- 8x- 48= 0. I presume you know that will factor as (x- a)(x- b) where ab= -48 and a+ b= 8. What are possible integer values for a and b?
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  5. #5
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    Re: Factoring

    (x-12)(x+4)

    x-12=0 x+4=0
    x=12 x=-4
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  6. #6
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    Re: Factoring

    Quote Originally Posted by catherinee View Post
    (x-12)(x+4)

    x-12=0 x+4=0
    x=12 x=-4
    bravissimo!
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  7. #7
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    Re: Factoring

    Perhaps "bravssima"?
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