Math Help - Can I re-arrange the formula to find "y"

1. Can I re-arrange the formula to find "y"

I have this formula that creates a graph:
y^2+3.29*y-0.073=x^2.125

I need to re-arrange it so I will be able to find "y" when I know "x", so it looks like:
y=.......

It is possible?

2. Re: Can I re-arrange the formula to find "y"

Solve y^2+a*y+b=0 for y, where a=? and b=?

3. Re: Can I re-arrange the formula to find "y"

I have this formula that creates a graph:
y^2+3.29*y-0.073=x^2.125

I need to re-arrange it so I will be able to find "y" when I know "x", so it looks like:
y=.......

It is possible?

basically you treat x2.125 as a constant and solve for y using the quadratic formula or some other means. Then substitute x2.125 back into to your solved for roots.

I get

$$y=0.005 \left(-\sqrt{40000 x^{2.125}+111161}-329\right)$$

and

$$y=0.005 \left(\sqrt{40000 x^{2.125}+111161}-329\right)$$

4. Re: Can I re-arrange the formula to find "y"

JJacquelin:
I guess to solve a*y^2+b*y+c=0 is y=(-b±√(b^2-4ac))/2a

romsek:
That does not work
I need the solution that would match this blue graph: http://freebookexchange.org/temp/Clipboard02.jpg

Equation Grapher

Current formula: y^2+3.29*y-0.073=x^2.125

The curve is correct, but it is not in a right place. (I'm really sorry for my total luck of math knowledge. I feel so dumb.)

I guess I should change my question:
Wow can I re-write formula (a*y^2+b*y-c=x^d) so if would look like (y=....)

5. Re: Can I re-arrange the formula to find "y"

If you can solve this: re-write formula (a*y^2+b*y-c=x^d) so if would look like (y=....)

It should be most optimal, elegant solution for computer to calculate fast.

Actually you might have even better solution for me.
I'm trying to write a formula that would match as close as possible this linear one (y=(x+0.60-2.80+0.49)*100/82.75)
You can see in red here: http://freebookexchange.org/temp/Clipboard03.jpg
But it can not go into negative as it does right now after x is less than 1.72

What I need is for it to make a gentle curve around x=2.5, y=0.95 and eventually eventually end up at x=0, y=0.25
(at x>2.5 and above it turns into straight line) "X" value will be supplied and can be anything from 0.25 up to 999 and I need to be able to calculate "y" as close as possible to the linear one with "y" ever going into negative.

Best I could come up with was (y^2+3.29*y-0.073=x^2.125) (Blue curve) by randomly sticking numbers into in on Equation Grapher

Eventually formula will be plugged into computer so it should be as simple as possible to assure fast calculations.

As a thank you, I will order for you any book of your choice (or anything else) from Amazon (as long as it is under \$25.00) if you provide me with shipping address.

6. Re: Can I re-arrange the formula to find "y"

y^2+3.29*y-0.073=x^2.125
y^2+3.29*y+(-0.073-x^2.125)=0
a = 3.29
b = (-0.073-x^2.125)
Solve y^2+a*y+b=0 for y.
Then replace a and b by the terms above.

7. Re: Can I re-arrange the formula to find "y"

1. a*y^2 + b*y + c = x^2.125
2. a*y^2 + b*y + (c-x^2.125)=0
3. y=(-b+√(b^2-4*a*(c-x^2.125)))/2*a

1. 1*y^2+3.29*y-0.073=x^2.125
2. 1*y^2+3.29*y+(-0.073-x^2.125)=0
3. a=1, b = 3.29, c = (-0.073-x^2.125)
4. y=(-3.29+√(3.29^2-4*(-0.073-x^2.125)))/2 (Which one is faster for computer to calculate? each millisecond counts)
5. y=(-3.29+√(11.1161+4*x^2.125))/2 (Which one is faster for computer to calculate? each millisecond counts)
6. y=√(11.1161+4*x^2.125)/2-1.645 (Which one is faster for computer to calculate? each millisecond counts)

It worked!!!!.... Thank you so much JJacquelin. Would you like a gift from Amazon as promised? Just send me a link to what it is you would like and your shipping address. Also thank you for not giving full answer and making me work a little, I feel little bit better about myself.

8. Re: Can I re-arrange the formula to find "y"

it didn't work because you didn't input the correct formula into your grapher. The 329 is outside the radical.