# Math Help - Simplify a Radical

1. ## Simplify a Radical

Is that the correct answer to the problem?

I got in radicals: 6 and 11, $x^6, y{^14}, y$

2. Originally Posted by fluffy_penguin

Is that the correct answer to the problem?

I got in radicals: 6 and 11, $x^6, y{^14}, y$
No, it isn't right. You forgot to take the square roots of $x^6$ and $y^{14}$.

$\sqrt{396x^6y^{15}}$

$= \sqrt{36x^6y^{14} \cdot 11y}$

$= \sqrt{36} \sqrt{x^6} \sqrt{y^14} \sqrt{11y}$

$= 6x^3y^7 \sqrt{11y}$

-Dan