Need some help here..
Consider the function f(x) = x / x+ 2
a) show that f'(x) > 0 for all x in the domain
b) State the equation of the horizontal asymptote of y = f(x)
Thanks
You mean f(x)= x/(x+ 2), right? What you wrote is f(x)= 1+ 2= 3!
What is the derivative? Do you know the "quotient rule"?a) show that f'(x) > 0 for all x in the domain
Dividing both numerator and denominator of $\displaystyle f(x)= \frac{x}{x+ 1}$ givesb) State the equation of the horizontal asymptote of y = f(x)
$\displaystyle \frac{1}{1+ \frac{1}{x}}$
What happens as x "goes to infinity"?
Thanks