I solved this and I got -n for both a) and b) . Am I just tired and can't do math any more or what ????
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Originally Posted by sakonpure6 I solved this and I got -n for both a) and b) . Am I just tired and can't do math any more or what ???? $\displaystyle \cos(\pi+x)=\cos(\pi)\cos(x)-\sin(\pi)\sin(x)=-\cos(x)=-n$ $\displaystyle \sin(\frac{3\pi}{2}+x)=\sin(\frac{3\pi}{2})\cos(x) +\cos(\frac{3\pi}{2})\sin(x)=-\cos(x)=-n$ looks like you got both right to me.
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