Hi I am stuck on a factoring : x^6 - 124x^3 -125 Is this in a way a sum/difference of cubes?? Here is what I tried and where I got stuck:
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Suggest you just suppose x^3 = y, the question becomes y^2 - 124 y - 125 = ( y - 125) ( y+1) = ( x^3 - 5^3) ( x^3 + 1^3) = ( x-5) ( x^2 + 5x + 25) ( x + 1 ) ( x^2 - x + 1) These are the factors
Oh i see, tricky stuff!!! Thank you!
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