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Math Help - Area of a rectangle

  1. #1
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    Area of a rectangle

    I am stuck with this question... Can anyone help please:

    A rectangle is formed by doubling both the length and the width of a rectangle.

    What is the area, in cm2, of this new rectangle?

    the length is (a+3) cm
    the width is 2 cm


    Is the answer:

    = 2(a+3) x 2squared
    = 4 (2a + 6)
    = 8a + 24 cmsquared
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  2. #2
    MHF Contributor ebaines's Avatar
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    Re: Area of a rectangle

    Yes, that's correct. If the original rectangle has dimensions L=a+3 cm and W=2, then doubling both gives new dimensions of L= 2(a+3) cm =2a+6 cm, and W = 2(2cm) = 4 cm. The area of the new rectangle is then L x W = (2a+6 cm)(4 cm) = 8a +24 cm^2.
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  3. #3
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    Re: Area of a rectangle

    Quote Originally Posted by Natasha1 View Post
    I am stuck with this question... Can anyone help please:

    A rectangle is formed by doubling both the length and the width of a rectangle.

    What is the area, in cm2, of this new rectangle?

    the length is (a+3) cm
    the width is 2 cm
    The length and width of which rectangle? If a+ 3 and 2 are the length and the width of the first rectangle and the new rectangle "is formed by doubling both the length and the width of a rectangle" then the new rectangle has length 2(a+ 3)= 2a+ 6 and width 4.


    Is the answer:

    = 2(a+3) x 2squared
    = 4 (2a + 6)
    = 8a + 24 cmsquared
    Yes, that is correct although your writing "2 squared" fooled me for a moment! you are multiplying both length and width by 2 so the new length is 2(a+ 3)= 2a+ 6 and the new width is 2(2)= 2 squared= 4.
    Thanks from Natasha1
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