# Thread: Area of a rectangle

1. ## Area of a rectangle

I am stuck with this question... Can anyone help please:

A rectangle is formed by doubling both the length and the width of a rectangle.

What is the area, in cm2, of this new rectangle?

the length is (a+3) cm
the width is 2 cm

= 2(a+3) x 2squared
= 4 (2a + 6)
= 8a + 24 cmsquared

2. ## Re: Area of a rectangle

Yes, that's correct. If the original rectangle has dimensions L=a+3 cm and W=2, then doubling both gives new dimensions of L= 2(a+3) cm =2a+6 cm, and W = 2(2cm) = 4 cm. The area of the new rectangle is then L x W = (2a+6 cm)(4 cm) = 8a +24 cm^2.

3. ## Re: Area of a rectangle

Originally Posted by Natasha1
I am stuck with this question... Can anyone help please:

A rectangle is formed by doubling both the length and the width of a rectangle.

What is the area, in cm2, of this new rectangle?

the length is (a+3) cm
the width is 2 cm
The length and width of which rectangle? If a+ 3 and 2 are the length and the width of the first rectangle and the new rectangle "is formed by doubling both the length and the width of a rectangle" then the new rectangle has length 2(a+ 3)= 2a+ 6 and width 4.