Yes, that's correct. If the original rectangle has dimensions L=a+3 cm and W=2, then doubling both gives new dimensions of L= 2(a+3) cm =2a+6 cm, and W = 2(2cm) = 4 cm. The area of the new rectangle is then L x W = (2a+6 cm)(4 cm) = 8a +24 cm^2.
I am stuck with this question... Can anyone help please:
A rectangle is formed by doubling both the length and the width of a rectangle.
What is the area, in cm2, of this new rectangle?
the length is (a+3) cm
the width is 2 cm
Is the answer:
= 2(a+3) x 2squared
= 4 (2a + 6)
= 8a + 24 cmsquared
Yes, that's correct. If the original rectangle has dimensions L=a+3 cm and W=2, then doubling both gives new dimensions of L= 2(a+3) cm =2a+6 cm, and W = 2(2cm) = 4 cm. The area of the new rectangle is then L x W = (2a+6 cm)(4 cm) = 8a +24 cm^2.
The length and width of which rectangle? If a+ 3 and 2 are the length and the width of the first rectangle and the new rectangle "is formed by doubling both the length and the width of a rectangle" then the new rectangle has length 2(a+ 3)= 2a+ 6 and width 4.
Yes, that is correct although your writing "2 squared" fooled me for a moment! you are multiplying both length and width by 2 so the new length is 2(a+ 3)= 2a+ 6 and the new width is 2(2)= 2 squared= 4.Is the answer:
= 2(a+3) x 2squared
= 4 (2a + 6)
= 8a + 24 cmsquared