I have been asked a question by an indonesian student. This is the original question.
nilai maksimum f(x,y)=4x+12y pada x+2y<8;3x+2y<12;x>0;y>0 adalah
I ran this through 2 translators and they both gave this
The maximum value of f (x, y) = 4x +12 y on x +2y <8; 3x +2y <12; x> 0; y> 0 is
I am not sure what this means.
I assume it means find the maximum value of 4x+12y given that all the other inequalities are constraints
I have graphed the restricted area and
I have looked at the value of 4x+12y on each of the intersection points And the highest value is 48 at (0,4)
I think this is the answer but I think i should have a much better argument as to why.
Would anyone like to offer any suggestions/help?