$\displaystyle \begin{pmatrix} 2&1\\-4&0\\-3&2\end{pmatrix} \begin{pmatrix} 2 \\ 3 \end{pmatrix} = \begin{pmatrix} 7\\-8\\0 \end{pmatrix} $ is this correct ?
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Originally Posted by Tweety $\displaystyle \begin{pmatrix} 2&1\\-4&0\\-3&2\end{pmatrix} \begin{pmatrix} 2 \\ 3 \end{pmatrix} = \begin{pmatrix} 7\\{\color{red}-8}\\0 \end{pmatrix} $ is this correct ? No it is not. Try again.
what part is wrong ? -8? -4x2 + 3x0 = -8?
Originally Posted by Tweety what part is wrong ? -8? -4x2 + 3x0 = -8? You are correct. Sorry for the mistake.
The OP's answer is correct.
yes it is correct
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