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Math Help - Problem with basic explanation of algebra problem

  1. #1
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    Problem with basic explanation of algebra problem

    So here's the problem. 2 X (8-2y/4) -y =-2. The author says that he simplifies the equation by adding 4 to both sides and gets this 2 x (8-2y) -4y = -8. So, my question is why is the 2 in the front not an 8? i.e, 8 x (8-2y) - 4y= -8.

    Thanks for the help.
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  2. #2
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    Re: Problem with basic explanation of algebra problem

    Quote Originally Posted by bkruss View Post
    So here's the problem. 2 X (8-2y/4) -y =-2. The author says that he simplifies the equation by adding 4 to both sides and gets this 2 x (8-2y) -4y = -8. So, my question is why is the 2 in the front not an 8? i.e, 8 x (8-2y) - 4y= -8.
    First, write it correctly: \dfrac{2(8-2y)}{4}-y=-2.

    Now I hope he/she said multiply both sides by 4. NOT ADD.

    2(8-2y)-4y=-8. The 2 is in the numerator, the 4 is in denominator and divides off.
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  3. #3
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    Re: Problem with basic explanation of algebra problem

    Alternatively, 4 times both slides of \dfrac{2(8- 2y)}{4}- y= 2 is \frac{8(8- 2y)}{4}- 4y= -8 so there is an "8" in front, in the numerator. But, of course, \dfrac{8}{4}= 2.
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