3 Ix+3I = Ix-3I+2x

I used the letter (I) and the line for the absolute value. Thanks for your help.

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- Nov 11th 2007, 05:14 PMMathMackAbsolute Value equation
3 Ix+3I = Ix-3I+2x

I used the letter (I) and the line for the absolute value. Thanks for your help. - Nov 11th 2007, 08:46 PMtopsquark
By the way, your keyboard has a key | that is just above the "enter" key. Use that for absolute value.

$\displaystyle 3|x + 3| = |x - 3| + 2x$

There are 3 intervals you need to consider: $\displaystyle (-\infty, -3),~(-3, 3),~(3, \infty)$

On $\displaystyle (-\infty, -3)$ the equation reads

$\displaystyle 3(-x - 3) = -(x - 3) + 2x$

On $\displaystyle (-3, 3)$ the equation reads

$\displaystyle 3(x + 3) = -(x - 3) + 2x$

On $\displaystyle (3, \infty)$ the equation reads

$\displaystyle 3(x + 3) = (x - 3) + 2x$

One, or more, of these equations will give you your solution set.

-Dan - Nov 11th 2007, 08:54 PMMathMack
I'm a little confused, so if I do one of them equations it will give me the answer or what I need for the problem?

- Nov 11th 2007, 09:38 PMtopsquark