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Math Help - How to solve a quadratic which has a term with a square root over the variable?

  1. #1
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    How to solve a quadratic which has a term with a square root over the variable?

    How to solve a quadratic which has a term with a square root over the variable?
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  2. #2
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    Re: How to solve a quadratic which has a term with a square root over the variable?

    Hey AaPa.

    Can you show us what equation/expression/function you are talking about?
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    Re: How to solve a quadratic which has a term with a square root over the variable?

    like

    x^2+2x+3+4(sqrt(x))=0
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    Re: How to solve a quadratic which has a term with a square root over the variable?

    Hello, AaPa!

    How to solve: . x^2+2x+3+4\sqrt{x} \:=\:0

    This is not a quadratic.

    You have: . x^2 + 2x + 4\sqrt{x} + 3 \:=\:0

    Let \sqrt{x}=u \quad\Rightarrow\quad x = u^2

    The equation becomes: . u^4 + 2u^2 + 4u + 3 \:=\:0

    And you have a quartic to solve.
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    Re: How to solve a quadratic which has a term with a square root over the variable?

    Thanks.
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