Results 1 to 3 of 3
Like Tree1Thanks
  • 1 Post By HallsofIvy

Math Help - Finding the image point on an inverse Exponential Function.

  1. #1
    Senior Member sakonpure6's Avatar
    Joined
    Sep 2012
    From
    Canada
    Posts
    383
    Thanks
    28

    Finding the image point on an inverse Exponential Function.

    There is a point (1,0) of the parent function f(x) = log x find the image point on f(x)= 5 log(x-2) which is the same as y= 5f(x) . I know how to do this by applying appropriate transformations, however how come when I use the the algebraic approach found here How to find corresponding coordinates? , it does not work?

    The answer is I found is (0,3).
    Thank you.
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor

    Joined
    Apr 2005
    Posts
    15,414
    Thanks
    1328

    Re: Finding the image point on an inverse Exponential Function.

    No, if you are taking f(x)= log(x), y= 5 log(x- 1) is NOT "y= 5f(x)". It is, rather, y= 5 f(x- 1). Generally speaking changes inside the "parent" function are changes to x and reflect horizontal changes to the graph. For example, f(1)= log(1)= 0 so that f(2)= log(2-1)= 0 so that, in effect, the graph is shifted one place to the right. Changes outside the parent function are changes to y, vertical changes. Multiplying by 5 stretches the graph vertically by a multiplier of 5.
    Thanks from sakonpure6
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Senior Member sakonpure6's Avatar
    Joined
    Sep 2012
    From
    Canada
    Posts
    383
    Thanks
    28

    Re: Finding the image point on an inverse Exponential Function.

    O sorry that was a typo, I know what you mean, but If you actually try solving the problem using the method mentioned in the link it does not work. Am I missing something?
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Finding Image of a point.
    Posted in the Algebra Forum
    Replies: 1
    Last Post: September 9th 2013, 06:37 PM
  2. Finding the Image of a point
    Posted in the Algebra Forum
    Replies: 4
    Last Post: September 15th 2012, 02:25 PM
  3. Inverse image of a function defined on R
    Posted in the Differential Geometry Forum
    Replies: 1
    Last Post: October 12th 2011, 02:05 AM
  4. Replies: 2
    Last Post: September 8th 2010, 12:27 AM
  5. Replies: 2
    Last Post: September 27th 2009, 08:37 PM

Search Tags


/mathhelpforum @mathhelpforum