# Boolean Associative Law

• Dec 5th 2013, 11:34 AM
Jarod_C
Boolean Associative Law
Hi, I have a couple of questions about Boolean. I have to identity which law is being used. I have to pick which one off a numbered list. I don't know if this list is numbered the same everywhere, so I've posted it HERE.

Below is an example of associative law #12, correct?

$(\overline A\bullet \overline B)(A\overline B)=\overline A\bullet A \bullet \overline B \bullet \overline B$

And I'm not as sure on this one, but I'm going to guess distributive law #15.

$(\overline{A\overline{BC}})(AC)+AB=(\overline A+ \overline{\overline B}\overline{\overline C}}})(AC)+AB$

• Dec 5th 2013, 12:00 PM
romsek
Re: Boolean Associative Law
Quote:

Originally Posted by Jarod_C
Hi, I have a couple of questions about Boolean. I have to identity which law is being used. I have to pick which one off a numbered list. I don't know if this list is numbered the same everywhere, so I've posted it HERE.

Below is an example of associative law #12, correct?

$(\overline A\bullet \overline B)(A\overline B)=\overline A\bullet A \bullet \overline B \bullet \overline B$

And I'm not as sure on this one, but I'm going to guess distributive law #15.

$(\overline{A\overline{BC}})(AC)+AB=(\overline A+ \overline{\overline B}\overline{\overline C}}})(AC)+AB$

The top one is a combination of both the associative law of multiplication and DeMorgan's law. (#12 and #20)

The bottom one does no distribution so I don't know why you'd choose that one. It could, but it doesn't.

It uses #19 to obtain $\overline{A \overline{B C}}=\bar{A}+\overline{\overline{B C}}$
• Dec 5th 2013, 12:03 PM
Jarod_C
Re: Boolean Associative Law
Thanks for the help. Also, I just click the star to thank you, right?
• Dec 5th 2013, 12:11 PM
romsek
Re: Boolean Associative Law
You're welcome. I think there's a thanks link that appears with a mouseover near the bottom right hand corner.