On a certain day, 25% of the people at a park were women. The number of men, boys and girls at the same park were in the ratio 8:5:2 respectively. If there were 54 more adults than children, how many people were at the park that day ?

Results 1 to 3 of 3

- November 25th 2013, 06:32 PM #1

- Joined
- Nov 2013
- From
- Boston
- Posts
- 1

## Need help with this problem

On a certain day, 25% of the people at a park were women. The number of men, boys and girls at the same park were in the ratio 8:5:2 respectively. If there were 54 more adults than children, how many people were at the park that day ?

- November 25th 2013, 06:39 PM #2

- Joined
- Nov 2013
- From
- California
- Posts
- 2,801
- Thanks
- 1154

- November 25th 2013, 08:21 PM #3

- Joined
- Jul 2012
- From
- INDIA
- Posts
- 848
- Thanks
- 216

## Re: Need help with this problem

let us say there were 100 people in park, out of these 25 were women and 75 rest, that is men , boys and girls. ratio 8:5:2 so we divide 75 in this ratio and we get 40 men, 25 boys and 10 girls. boys + girls = 35 so we have 5 men more that number of children.

When there are 5 men more than children we have people in park = 100

When there are 1 men more than children we have people in park = 100/ 5 = 20

When there are 54 men more than children we have people in park = 54 * 20 = 1080

We can also get the result by assuming that there were x people in the park initially. That you can try.