# Equation that makes my life harder

• Nov 22nd 2013, 09:00 AM
imclaren
Equation that makes my life harder
Hello everybody.
I have an equation that I am trying to solve for 7 hours. But nothing made me success, unfortunately. So I decided to ask for help there.
Attachment 29790
I will be very lucky if somebody helps me to solve my problem.

P.S.: Sorry for my English, I am only beginner now.
• Nov 22nd 2013, 11:02 AM
JJacquelin
Re: Equation that makes my life harder
Let x=2X
(4+sqrt(15))^X + (4-sqrt(15))^X = 8^X
An obvious solution is X=1 . So x=2.
• Nov 22nd 2013, 06:28 PM
imclaren
Re: Equation that makes my life harder
Thank you for finding the solution but I have already found it.
I must proof that this equation has only one decision. (I can't proof it using graph because it is enough difficult to construct y=(4+sqrt(15))^X + (4-sqrt(15))^X without, for example, WolframAlpha).
• Nov 23rd 2013, 12:13 AM
Idea
Re: Equation that makes my life harder
Let $a = 4 + \sqrt{15}$ and $b = 4 - \sqrt{15}$

so that

$a^{x/2} + b^{x/2} = 8^{x/2}$

Multiply this equation by $a^{x/2}$

$a^x + 1 = \left(\sqrt{8a}\right)^x$ since $a b=1$
• Nov 23rd 2013, 06:37 PM
imclaren
Re: Equation that makes my life harder
I'm probably idiot, but I don't really know, how to solve this equation. Sorry. Attachment 29801
• Nov 23rd 2013, 10:12 PM
JJacquelin
Re: Equation that makes my life harder
Let ax=t2
• Nov 23rd 2013, 10:29 PM
Idea
Re: Equation that makes my life harder
I don't know how to solve this equation either and I don't see how letting $a^x = t^2$ will help.

On the other hand if you graph the function

$f(x) = a^x+1 - \left(\sqrt{8a}\right)^x$ with $x > 0$

you will notice that it is decreasing and that $f(2) = 0$

This shows that $x = 2$ is the only solution

To prove that it is the only solution you would have to show $f ' (x) < 0$
• Nov 24th 2013, 12:00 AM
JJacquelin
Re: Equation that makes my life harder
Quote:

Originally Posted by Idea
I don't know how to solve this equation either and I don't see how letting $a^x = t^2$ will help.

On the other hand if you graph the function

$f(x) = a^x+1 - \left(\sqrt{8a}\right)^x$ with $x > 0$

you will notice that it is decreasing and that $f(2) = 0$

This shows that $x = 2$ is the only solution

To prove that it is the only solution you would have to show $f ' (x) < 0$

My mistake ! You are right.