Hey Tweety.
Did you plot the figure geometrically? Also remember to break things up into triangles and add the areas.
Hint: The length of the vector |axb| gives the area of the triangle that is enclosed within the vectors a and b.
Find the area of the parallelogram with vertices at (1,4), (2,-5), (5,-2) and (4,7)
I know the formula is ad-bc
however how do i work out what the vectors (a,b) and (c,d) are?
its suppose to be (3,3) and (1,-9)
I have drawn a diagram, but it still does not help, what are the non-parallel edges?
Hey Tweety.
Did you plot the figure geometrically? Also remember to break things up into triangles and add the areas.
Hint: The length of the vector |axb| gives the area of the triangle that is enclosed within the vectors a and b.
To find the coordinates of a vector, subtract the coordinates of the beginning from those of the end.
This follows from the definition of coordinates and operations of vectors. In my course, the coordinates of a point are by definition the coordinates of the radius-vector to that point. That is, if O is the origin, the coordinates of a point A are the coordinates of the vector OA. Now, a vector AB equals OB - OA, so the coordinates of AB are the coordinates of B minus the coordinates of A.