Re: parallelogram area help

Hey Tweety.

Did you plot the figure geometrically? Also remember to break things up into triangles and add the areas.

Hint: The length of the vector |axb| gives the area of the triangle that is enclosed within the vectors a and b.

Re: parallelogram area help

No, chiro. |a x b| gives the area of the **parallelogram** having vectors a and b as two sides. The area of the triangle is (1/2)|a x b|.

Re: parallelogram area help

Yes you are spot on: thanks for picking that up! (1/2absin(C) = 1/2 |axb|).

Re: parallelogram area help

Quote:

Originally Posted by

**Tweety** Find the area of the parallelogram with vertices at (1,4), (2,-5), (5,-2) and (4,7)

I know the formula is ad-bc

however how do i work out what the vectors (a,b) and (c,d) are?

its suppose to be (3,3) and (1,-9)

I have drawn a diagram, but it still does not help, what are the non-parallel edges?

@Tweety, I am constantly amazed how little you seem to know about questions that you are asked to solve.

If you have not been taught this theorem then your course is a **SHAM**

Theorem: If are adjacent sides of a parallelogram then

is the **area** of that parallelogram.

Re: parallelogram area help

errmm well I know this formula, but my problem was I did not know 'how to apply it, and also I missed classes when this was being taught so i am just reading it off a text book......

Re: parallelogram area help

To find the coordinates of a vector, subtract the coordinates of the beginning from those of the end.

This follows from the definition of coordinates and operations of vectors. In my course, the coordinates of a point are by definition the coordinates of the radius-vector to that point. That is, if O is the origin, the coordinates of a point A are the coordinates of the vector OA. Now, a vector AB equals OB - OA, so the coordinates of AB are the coordinates of B minus the coordinates of A.