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Math Help - need to obtain variable for this equation

  1. #1
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    need to obtain variable for this equation

    Hi guys i am stuck on the following problem

    275*(1/1,0)*((5,5-(h/30))/3)*((30*h^2)/6)=288*10^3

    I am stuck on this problem

    Some hints i got is that it should be 11
    Whats the easiest way to solve it

    Its supposed to be simplified to
    5,5*h^2- (h^3/30)=628

    Would be grateful if someone could explain and show me the steps to obtain h thoroughly
    I am also unsure exactly how to continue from the simplified version

    Thank you
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  2. #2
    Forum Admin topsquark's Avatar
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    Re: need to obtain variable for this equation

    Quote Originally Posted by Riazy View Post
    Hi guys i am stuck on the following problem

    275*(1/1,0)*((5,5-(h/30))/3)*((30*h^2)/6)=288*10^3

    I am stuck on this problem

    Some hints i got is that it should be 11
    Whats the easiest way to solve it

    Its supposed to be simplified to
    5,5*h^2- (h^3/30)=628

    Would be grateful if someone could explain and show me the steps to obtain h thoroughly
    I am also unsure exactly how to continue from the simplified version

    Thank you
    One quick question. I know that 5,5 is 5.5 in other places. But what does this mean? "1/1,0"? It looks like you are dividing 1 by 1 but why put it as 1/1,0?

    Assuming that 1/1,0 = 1, then
    275 \frac{5,5-\frac{h}{30}}{3} \cdot \frac{30*h^2}{6} = 288 \times 10^3

    Mulitply both sides by 18:
    275 \left ( 5,5-\frac{h}{30} \right ) \cdot ( 30*h^2 ) = 18 \cdot 288 \times 10^3

    Multiply out the LHS:
    275 \left ( 5,5-\frac{h}{30} \right ) \cdot ( 30*h^2 ) = 18 \cdot 288 \times 10^3

    275(165h^2 - h^3) = 5184 \times 10^3 = 5,184 \times 10^6

    This is evidently not the equation you were supposed to derive, but the method to solve it will be the same.

    -Dan
    Thanks from Riazy
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    Re: need to obtain variable for this equation

    Thanks dan. Actually gamma m 0 is a value for calculations i just wrote from the tables its 1,0. Thank you again. 1,0 and 1.0 is same
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  4. #4
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    Re: need to obtain variable for this equation

    I get h = 165. Am i doing something wrong it should be 11. I mean h = 11
    Could you show me how you proceed?


    Quote Originally Posted by topsquark View Post
    One quick question. I know that 5,5 is 5.5 in other places. But what does this mean? "1/1,0"? It looks like you are dividing 1 by 1 but why put it as 1/1,0?

    Assuming that 1/1,0 = 1, then
    275 \frac{5,5-\frac{h}{30}}{3} \cdot \frac{30*h^2}{6} = 288 \times 10^3

    Mulitply both sides by 18:
    275 \left ( 5,5-\frac{h}{30} \right ) \cdot ( 30*h^2 ) = 18 \cdot 288 \times 10^3

    Multiply out the LHS:
    275 \left ( 5,5-\frac{h}{30} \right ) \cdot ( 30*h^2 ) = 18 \cdot 288 \times 10^3

    275(165h^2 - h^3) = 5184 \times 10^3 = 5,184 \times 10^6

    This is evidently not the equation you were supposed to derive, but the method to solve it will be the same.

    -Dan
    Follow Math Help Forum on Facebook and Google+

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