need to obtain variable for this equation

Hi guys i am stuck on the following problem

275*(1/1,0)*((5,5-(h/30))/3)*((30*h^2)/6)=288*10^3

I am stuck on this problem

Some hints i got is that it should be 11

Whats the easiest way to solve it

Its supposed to be simplified to

5,5*h^2- (h^3/30)=628

Would be grateful if someone could explain and show me the steps to obtain h thoroughly

I am also unsure exactly how to continue from the simplified version

Thank you

Re: need to obtain variable for this equation

Quote:

Originally Posted by

**Riazy** Hi guys i am stuck on the following problem

275*(1/1,0)*((5,5-(h/30))/3)*((30*h^2)/6)=288*10^3

I am stuck on this problem

Some hints i got is that it should be 11

Whats the easiest way to solve it

Its supposed to be simplified to

5,5*h^2- (h^3/30)=628

Would be grateful if someone could explain and show me the steps to obtain h thoroughly

I am also unsure exactly how to continue from the simplified version

Thank you

One quick question. I know that 5,5 is 5.5 in other places. But what does this mean? "1/1,0"? It looks like you are dividing 1 by 1 but why put it as 1/1,0?

Assuming that 1/1,0 = 1, then

$\displaystyle 275 \frac{5,5-\frac{h}{30}}{3} \cdot \frac{30*h^2}{6} = 288 \times 10^3$

Mulitply both sides by 18:

$\displaystyle 275 \left ( 5,5-\frac{h}{30} \right ) \cdot ( 30*h^2 ) = 18 \cdot 288 \times 10^3$

Multiply out the LHS:

$\displaystyle 275 \left ( 5,5-\frac{h}{30} \right ) \cdot ( 30*h^2 ) = 18 \cdot 288 \times 10^3$

$\displaystyle 275(165h^2 - h^3) = 5184 \times 10^3 = 5,184 \times 10^6$

This is evidently not the equation you were supposed to derive, but the method to solve it will be the same.

-Dan

Re: need to obtain variable for this equation

Thanks dan. Actually gamma m 0 is a value for calculations i just wrote from the tables its 1,0. Thank you again. 1,0 and 1.0 is same

Re: need to obtain variable for this equation

I get h = 165. Am i doing something wrong it should be 11. I mean h = 11

Could you show me how you proceed?

Quote:

Originally Posted by

**topsquark** One quick question. I know that 5,5 is 5.5 in other places. But what does this mean? "1/1,0"? It looks like you are dividing 1 by 1 but why put it as 1/1,0?

Assuming that 1/1,0 = 1, then

$\displaystyle 275 \frac{5,5-\frac{h}{30}}{3} \cdot \frac{30*h^2}{6} = 288 \times 10^3$

Mulitply both sides by 18:

$\displaystyle 275 \left ( 5,5-\frac{h}{30} \right ) \cdot ( 30*h^2 ) = 18 \cdot 288 \times 10^3$

Multiply out the LHS:

$\displaystyle 275 \left ( 5,5-\frac{h}{30} \right ) \cdot ( 30*h^2 ) = 18 \cdot 288 \times 10^3$

$\displaystyle 275(165h^2 - h^3) = 5184 \times 10^3 = 5,184 \times 10^6$

This is evidently not the equation you were supposed to derive, but the method to solve it will be the same.

-Dan