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Thread: help

  1. #1
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    help

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  2. #2
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    Re: help

    In the second equation, solve for $\displaystyle \dfrac{1}{p}$.

    First $\displaystyle q = \dfrac{9}{2p}$. Then, multiply both sides by $\displaystyle \dfrac{2}{9}$. So, $\displaystyle \dfrac{2q}{9} = \dfrac{1}{p}$. Then $\displaystyle \dfrac{2q}{9} + \dfrac{1}{q} = 1$. Now, solve for $\displaystyle q$.
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  3. #3
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    Re: help

    Note: There are a number of ways to solve the system of equations. You first need an expression for $\displaystyle p$ in terms of $\displaystyle q$, so in the first equation, you could multiply both sides by $\displaystyle pq$. Then $\displaystyle q+p = pq$. Now, solve for $\displaystyle p$:

    $\displaystyle p-pq = -q$

    $\displaystyle p(1-q) = -q$

    $\displaystyle p = \dfrac{-q}{1-q} = \dfrac{q}{q-1}$

    Plug that into the second equation and solve for $\displaystyle q$.
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  4. #4
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    Re: help

    thank you I solved it
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